Thread: gawk asort normal comparison confusion

i'm new gawk. read asort function sorts data element values; when no sort function specified, in default order (which took numerical sort or lexicographic sort respectively). not understand why below output...

output:

code:

index: 4 - value: 4 index: 1 - value: 1 index: 2 - value: 2 index: 3 - value: 3

, independent on single letter choose xxx, long letter distinct other array indices a, g, , m.

command line entered:

code:

$ gawk 'begin{ >var["a"] = 1 >var["g"] = 2 >var["m"] = 3 >var["xxx"] = 4 >asort(var, test) >for (i in test) >print "index: " i, " - value:", test[i] }'

i didn't find reference default comparison criterion on gawk's man page, might have overlooked it. googling produces examples in lexicographic ordering works expected, i'm bit @ loss.


note:
- problem similar using asorti
- i'm working under ubuntu 10.04.

posted gnometorule

i'm new gawk. read asort function sorts data element values; when no sort function specified, in default order (which took numerical sort or lexicographic sort respectively). not understand why below output...

output:

code:

index: 4 - value: 4  index: 1 - value: 1  index: 2 - value: 2  index: 3 - value: 3

, independent on single letter choose xxx, long letter distinct other array indices a, g, , m.

command line entered:

code:

$ gawk 'begin{  >var["a"] = 1  >var["g"] = 2  >var["m"] = 3  >var["xxx"] = 4  >asort(var, test)  >for (i in test)  >print "index: " i, " - value:", test[i]  }'

i didn't find reference default comparison criterion on gawk's man page, might have overlooked it. googling produces examples in lexicographic ordering works expected, i'm bit @ loss.


note:
- problem similar using asorti
- i'm working under ubuntu 10.04.

i don't use gawk much, according documentation, indices of array not used, set of values.

next problem 'for (i in test)' seemingly ignores indices: returns values in random order.

produces sorted output, @ least:

code:

gawk 'begin{  var[1] = "1"  var[2] = "4"  var[3] = "3"  var[4] = "2"  asort(var, test)  (i=1; i<=length(test); i++)  print "index: " i, " - value:", test[i]  }'

Forum The Ubuntu Forum Community Ubuntu Specialised Support Development & Programming Programming Talk [SOLVED] gawk asort normal comparison confusion

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